实现节点筛选函数,调整节点数据表结构
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@@ -1,18 +1,67 @@
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package services
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import "platform/web/models"
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import (
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"encoding/json"
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"fmt"
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"platform/pkg/orm"
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)
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var Node = &nodeService{}
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type nodeService struct{}
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func (s *nodeService) Filter(userId int32, proto ChannelProtocol, count int, config ...NodeFilterConfig) ([]*models.Node, error) {
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func (s *nodeService) Filter(userId int32, count int, config ...NodeFilterConfig) ([]*FilteredNode, error) {
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_config := NodeFilterConfig{}
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if len(config) > 0 {
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_config = config[0]
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}
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return make([]*models.Node, 0), nil
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// 筛选符合条件且未分配给用户过的节点
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// 静态条件:省,市,运营商
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// 排序方式,1.分配给该用户的次数 2.分配给全部用户的次数 3.todo 节点的健康状态
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var nodes []*FilteredNode
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orm.DB.Raw(filterSqlRaw, userId, _config.Isp, _config.Prov, _config.City).
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Limit(count).
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Find(&nodes)
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rs, _ := json.Marshal(nodes)
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fmt.Printf(string(rs))
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// 返回节点列表
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return nodes, nil
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}
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type NodeFilterConfig struct {
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province string
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city string
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provider string
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Isp string
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Prov string
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City string
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}
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const filterSqlRaw = `
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select
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n.id as id,
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n.name as name,
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n.fwd_port as port,
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count(c.*) as total,
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count(c.*) filter ( where c.user_id = ? ) as assigned
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from
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node n
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left join public.channel c
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on n.id = c.node_id and c.expiration > now() and c.deleted_at is null
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where
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n.isp = ? and
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n.prov = ? and
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n.city = ?
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group by
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n.id
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order by
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assigned, total
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`
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type FilteredNode struct {
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Id int32 `json:"id"`
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Name string `json:"name"`
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Port int32 `json:"port"`
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Total int32 `json:"total"`
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Assigned int32 `json:"assigned"`
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}
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